Last Updated on September 19, 2026 by Maged kamel
- List of compression member posts- part 1.
- Steel columns and Euler's formula- Two parts.
- Buckling for columns – effective length factors.
- Column compressive Strength- Analysis problem.
- How to compute critical stress using Table 4-22?
- A Solved Problem 4-9 for available compressive Strength.
- Alignment charts for columns.
- Solved problem 7-1 for the alignment chart for columns.
- Solved Problem 13-28 For Compression Members.
- Solved Problems for column analysis.
- 10- Introduction to Local Buckling.
List of compression member posts- part 1.
Steel columns and Euler’s formula- Two parts.
The first Post, Post 1 on compression members, includes four points. The first point is: What is the definition of compression members?
The second point will be Euler’s equation, including its derivation. The third point is what Buckling is. The fourth point is how to estimate the critical Load. The next image shows the Euler equation for stresses.

This links to the first Post.
This is a Link to the second Post, 1A.
You can view and download the PDF file for Post 1 and 1A by clicking the following Button.
Buckling for columns – effective length factors.
This is the third Post in the Compression Member Posts-part 1 series, which discusses column Buckling. If we apply an axial force to a straight column and gradually increase it, the Load will eventually reach a Value known as Pcr, at which the column will buckle.
As stated earlier, Pcr is the critical Buckling Load. Buckling occurs when a straight column is subjected to a compressive force. It is converted into a bending Moment, as shown in Figure 1b earlier. Later, it becomes deformed. A solved problem is given, as shown.

Buckling is identified as a failure limit state, and the failure mode for that column.
The Link to Post 2: Buckling for columns – effective length factors.
The Link to Post 2A: Introduction to Buckling for Columns-Part 2.
You can view and download the PDF file for Post 2 and 2A by clicking the following Button.
Column compressive Strength- Analysis problem.
This is the fifth Post in the compression member Posts (part 1), and it includes solved problem 4.2 from Prof. William T. Segui’s hand-solved problem 4.2 (estimate design compressive Strength).

This is the Link to Post 3: Column compressive Strength analysis problem.
This is the Link to Post 3a: Solved problem 4-2-how to find design compressive Strength?
You can view and download the PDF file for Post 3 by clicking the following Button.
You can view and download the PDF file for Post 3a by clicking the following Button.
How to compute critical stress using Table 4-22?
This is the 7th Post in the compression members series (Posts-part 1), which covers our subject: estimating compressive Strength using tables.
The controlling factor that distinguishes short columns from long columns is the criterion Kl/r. We evaluate the maximum Value in either the x- or y-direction.
The maximum kL/r Value will yield the minimum compressive Strength.
Link to Post 4: How to compute critical stress using Table 4-22? The following Post image explains the LRFD Value estimation using Table 4-22.

You can view and download the PDF for Post 4 by clicking the Button below.
A Solved Problem 4-9 for available compressive Strength.
This is the 8th Post in the compression member series (Posts-part 1) and includes solved problem 4-9.
A solved problem example from Prof. William T. Segui’s handbook: solved problem 4.9. A W12×58, 24 feet long, is pinned at both ends and braced in the weak direction at the third point, as shown in Figure 4.11. A992 steel is used.

Determine the available compressive Strength.
The Link to Post 5: A Solved Problem 4-9 for available compressive Strength.Post
You can view and download the PDF file for Post 5 by clicking the following Button.
Alignment charts for columns.
This is the 9th compression member Post (part 1), which includes a new topic: using the alignment chart for columns attached to frames, whether braced or not, created by Anderson and Wood.

However, this method is based on certain assumptions: that the column and Beam are elastic if those conditions are met, and that you should use the adjusted factor if the column is inelastic.
The Link to Post 6: Alignment charts for columns.
You can view and download the PDF file for Post 6 by clicking the following Button.
Solved problem 7-1 for the alignment chart for columns.
This is the 10th Post of the compression member Posts-part 1, which includes a solved problem 7.1 from Prof. McCormack’s book. Determine the effective length factor for each of the frame’s columns shown in Fig. 7. Suppose.

Suppose the frame is not braced against side-sway. Use the alignment charts in Fig. 7.2(b).
Link to Post 7: Solved Problem 7-1 for the column alignment chart.
You can view and download the PDF file for Post 7 by clicking the following Button.
Solved Problem 13-28 For Compression Members.
This is the 11th Post in the Compression Member Posts series, which includes solved problem 13.28. The example is from M.Iqbal. A W12 x 50 is used as a column, as shown. Fy = 50 ksi. The support is fixed at the bottom and has a guide roller at the top. Estimate the available axial compression Strength in kips.

Select the correct answer from the following options 1) 90 kips, 2)270 kips 3)360 kips 4)660 kips.
The Link: Post 8: Solved Problem 13-28 for Compression Members.
You can view and download the PDF file for Post 8 by clicking the following Button.
Solved Problems for column analysis.
This is the 12th Post in the Compression Member Posts series, which includes two solved problems: 13.28A from M. Iqbal. It is used as a column, as shown. Fy = 50 ksi; the support is fixed at the bottom, and with a guide roller at the top, estimate the available axial compression Strength in kips.
Select the correct answer from the following options 1) 500 kips, 2) 460 kips 3)580 kips 4) 600 kips.
The second solved example is 13-28a.

This is Post 9: Solved Problems for column analysis.
You can view and download the PDF file for Post 9 by clicking the following Button.
10- Introduction to Local Buckling.
This is the 13th Post in the Compression Member Posts series, which includes: We have discussed local Buckling for beams, the local Buckling coefficient for flange-web beams, and the general Condition. There are three types: compact, noncompact, and slender sections.

This links to Post 10: Introduction to Local Buckling. This is part 1. Link to Post is the second part.
You can view and download the PDF file for Post 10 by clicking the following Button.
You can view and download the PDF file for Post 10a by clicking the following Button.
This links to the List of compression member posts, part 2.
This links to the List of compression Member Posts, part -3.
For a good Beginner’s Guide to the Steel Construction Manual, 14th ed. Chapter 7 – Concentrically Loaded Compression Members.
For a good Beginner’s Guide to the Steel Construction Manual, 15th ed. Chapter 7 – Concentrically Loaded Compression Members.
For a good Beginner’s Guide to the Steel Construction Manual, 16th ed. Chapter 7 – Concentrically Loaded Compression Members.