24b- Easy approach to solved problem-5-1-part 2.
In our post, we continue solving the Solved problem-5-1-part 2-2 in which the design of steel beam is governed by deflection.
24a- Easy approach to the solved problem-5-1-part 1-2
In our post we will introduce a solved problem-5-1-part 1-2 in which the design of steel beam is governed by deflection.
4-Derive the expression for L-U values for-3×3 matrix.
Step-by-step guide on how to derive the expression for L-U values for-3×3 matrix using Doolittle’s method?
18-A Review of portal frames-pin supports at base.
A review of portal frames subject, how to derive the internal forces for the portal frame with hinged supports at the base?
11-Moment of inertia Iy-Case-2 for a right-angle triangle.
How to get the moment of inertia for a right-angle triangle -Iy-case-2?The procedure is done by using a vertical strip. How to find polar moment of inertia Jo?
24- Easy approach to deflection of steel beams.
Deflection of steel beams, what are the disadvantages. What are the parameters controlling the deflection of steel beams?
10-Ix-the moment of inertia for a right-angle-Case-2.
How to get Ix-the moment of inertia for the right-angle triangle-Case-2? by using a horizontal strip, and the other method is to use a vertical strip.
3-How to solve for x-y by L-U Decomposition?
How to solve for x-y by L-U Decomposition? Illustration by Gauss elimination for L and U matrices.