9c- Practice problem-longitudinal weld of a c section

Last Updated on September 5, 2024 by Maged kamel

Practice problem-longitudinal weld of a C section.

This is a Practice problem for the longitudinal weld of a C section. It is case 2 for the shear lag factor table D3.1-CM-14 and can also be considered case 4 based on CM-15 and related specifications 2016. The Author’s answer is based on VCM#14.

This post will discuss two solutions: the first is based on CM-14, and the second on CM-15.

Practice problem 3-33 -longitudinal weld of a C section

Refer to Table 1-5 part-1 to get the flange thickness and the depth for the given C6x10.50 section.

The data for C6 x10.50  part -1 from table 1-5.

From Part 2 of Table 1-5, we get the x-bar distance.

The data for C6 x10.50 part -2 from table 1-5.

Shear lag factor U based on CM-14.

As we can see from the next picture, for Table D3.1, shear lag factors for connections to tension members, for longitudinal weld, it is case 4, but it is only for plates where the tension load is transmitted by longitudinal weld only. We will use case 2 instead.

The shear lag factor depends on the width of the joint w and establishes a relation between the length of connection L and width W.

1-From the given Data for the ASTMA36, we can get the yield stress Fy=36 ksi and the ultimate stress Fult equal to 58 ksi.

2—The following data can be found from the given section of C6x10.50. The first item is the area of the given section, which will equal 3.07 inches2.

The flange’s width is bf=2.03 inches, the flange thickness is 0.343 inches, and the width of the web is 0.314 inches. The overall depth will be 6 inches.

3- The connection length is given by the given section as equal to 5 inches.

4- The U value equals (1-xbar/L)=(1-0.5/5)=0.90.

Table D3.1 for CM-14 for shear lag factor

LRFD strength for Practice problem-longitudinal weld of a plate section-CM-14.

The gross area is the area of the C channel, which equals 3.07 inches2, while the effective area equals 0.9* 3.07 = 2.763 inches2.

The LRFD strength value for yielding equals 99.47 kips, while the LRFD strength due to rupture equals 120.19 kips.

We will select the lesser value as our final LRFD strength, 99.50 kips.

The LRFD design for the C channel based on Cm#14.

ASD strength for Practice problem-longitudinal weld of a plate section-CM-14

The gross area is the area of the C channel, which equals 3.07 inches2, while the effective area equals 0.9* 3.07 = 2.763 inches2.

The ASD strength value for yielding equals 66.18 kips, while the ASD strength due to rupture equals 80.13 kips.

We will select the lesser value as our final ASD strength, 66.18 kips.

The ASD design for the C channel based on Cm#14.

Shear lag factor U based on CM-15.

Referring to Table D3.1 for shear lag factor based on CM-15. The item number for shear lag factor U for the longitudinal weld to a C channel is case 4a. The U value is estimated by the product of (3L^2/3l^2*w2) multiplied by (1-1- xÌ…/ L).

The given section gives the connection length as equal to 5 inches.

The first term (3L^2/3l^2*w^2 equals (3*5^2/(3*5^2+5^2) to be multiplied by (1-(0.50/5), the final value of U=0.608.

Shear lag factor table based on CM-15

LRFD strength for Practice problem-longitudinal weld of a C section-CM-15.

The LRFD strength value for yielding equals 99.468 kips, while the LRFD strength due to rupture equals 81.24 kips.

We will select the lesser value as our final LRFD strength, which equals 81.24 kips. This indicates that the LRFD strength is governed by rupture.

LRFD strength for Practice problem-longitudinal weld of a C section.

ASD strength for the Practice problem-longitudinal weld of a C section-CM-15.

From the estimated calculation the selected ASD strength for the Practice problem-longitudinal weld of a C section-CM-15 is 54.14 kips, the full data is shown in the next slide image.

ASD strength for Practice problem-longitudinal weld of a C section.

Practice problem 3-3-6ths edition-longitudinal weld of a C section.

The next slide shows a practice problem 3-33 in the sixth edition of Prof. Mccormac’s book. The practice problem includes a C channel C8x11.50 with two longitudinal welds to a gusset plate at the back. I have solved that problem based on Cm#15; the U value is estimated based on item 4a, where w is the depth of the channel, and l is the average weld length. Please refer to the next slide for more information on the U estimate.

problem 3-33-sixth edition Longtudinal welds for c channel

The last slide includes a detailed estimate of both LRFd and Asd design strength values, which comply with the authors’ solution. Thank you very much.

The final design strengths.

The next post is post #9d, about how to get an Effective area for a staggered bolted angle.


Chapter 3 – Tension Members– A Beginner’s Guide to Structural Engineering is a great external resource.

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