Last Updated on September 14, 2026 by Maged kamel
CB-Bending coefficient-moment gradient factor part 1 for steel beams.
How do we estimate the CB-bending coefficient values for different loading types and bracing locations?
We will discuss a new subject: determining the CB-bending coefficient, also called the Moment gradient. We will calculate it for different loading and bracing. In all previous examples, we assumed Cb = 1, whether estimating the nominal design strength or designing a given section.

The different values of the CB bending coefficient, or Moment gradient factor Cb, are shown for the various types of loading for a simple Beam, as quoted from Prof. McCormack’s book.
The first figure shows a supported Beam with a uniformly distributed load W-ult k/ft.
The bracings are at the left support end and the proper support; each bracing is shown as an X mark.
For the unbraced length =l, the Value of Cb = 1.14 for the first case.
The following figure shows a supported Beam similar to the first case, but this Time, a bracing is added in the middle of the span.
So, in this case, we have three bracing points: the left side, the middle, and the right edge. The middle bracing is located at a distance =L/2 from the left support.
The uniformly distributed load = W, the Ultimate load Kips/Ft; in that case, the CB bending coefficient Value is =1.30.
The third case is for a supported Beam with a concentrated load applied at midspan. The CB-bending coefficient Value for this case is =1.32 for two bracings only.
The fourth case is for a supported Beam, similar to the third case but with three bracing members. The acting concentrated load is Pult. The Cb-bending coefficient-moment gradient for this case is 1.67.
Several cases involve two concentrated loads and bending moments acting at the supports. The Cb-bending coefficient Value for the last case is 2.27.

For statically indeterminate structures, we have a fixed-end Beam under a uniform load W, with two bracing points at the edges. The CB-bending coefficient Value is 2.38.
We have a CB-bending coefficient Value of 2.38 for the same Beam with three bracings.
The third case is for the fixed-end-supported Beam with a Pu load acting at midspan; the CB-bending coefficient is 1.92. The last case is for two fixed-end-supported beams with a Pu load acting in the middle and three bracings; the CB-bending coefficient is 2.27.

How do you estimate the Moment gradient CB for a supported Beam under a uniform loading?
Divide the distance between bracings into four equal parts, determine the Moment at each part, and then use the Cb equation. Please refer to the next slide image.

The equation we use to evaluate the Moment gradient factor Cb is Cb = 12.50*M-max/(2.50*Max + 3*MA + 4*Mb + 3*Mc); the sum of the denominator values is 2.50 + 3 + 4 + 3 = 12.50.
A is the first quarter-point. B is the second quarter-point. C is the third quarter-point.
For a supported Beam under uniformly distributed W-ult k/ft with two bracings, the first bracing is at the left edge, and the second bracing is at the proper support.
As we are familiar with a supported Beam under uniform loading, the maximum bending Moment is Mmax = W-Ult*L^2/8, where L is the span length.
This is the M-max for the Ma Value at the first-quarter point. First, estimate the reaction as W*L/2.
The Moment caused by the reaction = Wult*L/2*L4, opposed by a Moment for loading =Wul*(L/4)*1/2*(L/4)= the Moment Value Wul*l2/8-Wul*L2*1/32.
Finally, MA=3*Wult*L^2/32; due to symmetry, the Mc Value is the same as the MA. What is left is the Mb Value.

For the Mb Value, Wult*L^2/8; now we have all the information to estimate the Cb Value,
We have12.50*Wult*L^2/8/(2.5*Wult*L^2/8)+3* (3*Wult*L^2/32) +(4*3*Wult*L^2/8) +(3*Wul*L^2/32).

Take Wult*L^2 as a common factor; we have (2.50+ 18/32+4/8) for the denominator. The denominator sum=44/32. The CB equals (12.50*32)/(8×44) = 1.14, the same result as in the first case in Prof. McCormac’s shape.

How do we estimate the Moment gradient factor Cb for a fixed-end Beam under a uniform loading?
Let us check another case. L is the span length under a uniform loading, with two bracings at the edges of a Beam with two fixed supports. We know that the fixed-end Beam Moment equals Wu*L^2/12, while the positive Moment equals Wul*L^2/24.

For the fixed Beam, the fixed-end Moment M-Fe=Wul*L2/12 if the uniform loading = W-ult k/Ft.
We divide it into C, D, and E, where C is at L/4, D is in the middle, and E is at L/4 from the right support.
We draw the bending Moment diagram, but must estimate the reaction at the supports. We will perform the same exercise as before.
The reactions at supports A and B are equal, and each is Wu*L/2.
The Moment at point C=Wu*l/2*L/4-WUl^2/12-Wu*(L/4)*L/8=Wu*L^/96, due to symmetry at the middle of the Beam; MC = ME.

The Moment at Point D is equal to Wu*L^2/24, as expected. Please refer to the next slide image.

Applying the equation of Cb, we note that the maximum Moment is Wu*L^2/12, which is taken as a Value without the negative sign.
The numerator=12.50*Wul*L^2/12/(2.50*W*L^2/12+3*(1/96)*Wul*L^2+4*Wult*L^2/24+3*(Wul*L^2/96). So the denominator is: WulL^2(2.50/12)+(6/96)+(4/24).

Summing the values (2.50/12)+(6/96)+(4/24) results in (12.50/12). The coefficient of Moment (Cb), orMomentt gradient factor, for the fixed-end Beam is 2.38.
The Moment gradient factor Cb, or the coefficient of Moment, equals 2.38 for the fixed-end Beam.

Thanks a lot. I hope you like the content of Postis Post.
Please review and download the PDF file for Postis Post.
As an external resource –A Beginner’s Guide to Structural Engineering–Chapter 8 – Bending Members- 14th edition.
As an external resource –A Beginner’s Guide to Structural Engineering–Chapter 8 – Bending Members- 15th edition.
As an external resource –A Beginner’s Guide to Structural Engineering–Chapter 8 – Bending Members- 16th edition.
This is the complete list of all posts related to Cb:
1-Introduction to Cb-Bending coefficient part 1 for steel.- Post 17Postis post.
2- Cb-The coefficient of bending part 2 for steel beams-post 18-next post.
3-Old Cb Coefficient of bending for steel beams-post 18a.
4-Cb value-bracing at the midpoint of a beam-uniform load-Post 18b.
5-Cvaluee: bracing at the third point of a Beam, uniform load-Post 18C.
List of published posts –2a for the previous posts.