6-Video of a solved problem-Mohr’s circle of inertia case-1.

Last Updated on July 30, 2026 by Maged kamel

Video of a solved problem-Mohr’s circle of inertia case-1.

The video includes a practice problem that requires finding the principal moments of inertia in the left corner of a given right-angle triangle with a width of 150mm and a height of 200mm. This is a Typical Case 1 in which Ix is greater than Iy, and the product of inertia Ixy is positive.

Mohr’s circle of inertia must be used to obtain the maximum and minimum moments of inertia for the two major principal axes and their orientation with respect to the left corner point of the triangle. The video illustrates the required procedures for drawing a Mohr circle of inertia.

The Timestamps for the video are shown.

0:00 – The I_max and I_min for a given right angle at the left corner where b = 150 mm and height equals 200 mm.
3:10 – How to draw Mohr’s circle of inertia for Case 1 and the value of I_max and I_min?
6:03 – What is the value of 2θ_P1?
6:50 – How to find the Normal view and the principal axes in Mohr’s circle of inertia?
7:51 – Check I_polar and that I_uv equals zero.

For more information on the data included in a solved problem for Mohr’s circle of inertia, case 1. Refer to post 7 –A solved problem-case-1-Mohr’s circle of inertia.

For more information about case 1, please refer to post-6-Easy Approach to Mohr’s circle of inertia-First case.

The next video is Video 7– For Mohr’s circle of inertia case 2.

This link leads to a valuable external resource: a calculator for Cross-Section, Mass, Axial and polar area moment of Inertia, and Section Modulus.