Last Updated on October 21, 2026 by Maged kamel
Video of a solved problem-Mohr’s Circle of Inertia case 1.
The video includes a practice Problem that requires finding the principal moments of Inertia in the left corner of a given right-angle Triangle with a width of 150mm and a height of 200mm. This is a Typical Case 1, where Ix is greater than Iy, and the Product of Inertia Ixy is positive.
Use Mohr’s Circle of Inertia to find the maximum and minimum moments of Inertia for the two principal axes and their orientation relative to the Triangle’s left corner. The video illustrates the required procedures for drawing a Mohr Circle of Inertia.
The video timestamps are shown below.
- 0:00 – Imax and Imin for a given right angle at the left corner, where b = 150 mm and the height is 200 mm.
- 3:10 – How to draw Mohr’s Circle of Inertia for case 1 and the Value of Imax and Imin?
- 6:03 – What is the Value of 2θP1?
- 6:50 – How to find the Normal view and the principal axes in Mohr’s Circle of Inertia?
- 7:51 – Check I polar and that Iuv equals zero.
You can view or download the PDF data for this video by clicking the button.
For more information on the data included in a solved Problem for Mohr’s Circle of Inertia, case 1. Refer to Post 7 –A solved problem-case-1-Mohr’s Circle of Inertia.
For more information about case 1, refer to Post 6: Easy Approach to Mohr’s Circle of Inertia, First case.
The next video is Video 7: Mohr’s Circle of Inertia, Case 2.