Last Updated on September 2, 2026 by Maged kamel
Video for Mohr’s circle of inertia case-2.
The video illustrates the data for case 2 of Mohr’s circle of inertia, where Ix < Iy and ixy is positive. Mohr’s circle of inertia-second case can be found as an example in two cases. The first case is a rectangle with a height less than the width.
The first two steps are to draw the two orthogonal axes. The first axis represents the Moment of inertia values, Ix, Iy, and Imax, and the minimum values, while the second axis represents the values of the product of Inertia, Ixy.
Timestamps
- 0:00 – What are the cases for which Ix is smaller than Iy and Ixy is positive?
- 1:35 -What is the value of cos 2θP1 to get a maximum value of Ix?
- 3:00 – What is the value of cos 2θP2 to get a minimum value of Ix?
- 3:44 -The difference between the normal view and Mohr circle direction.
- 6:31 -How do we draw Mohr’s circle of inertia for case 2?
- 7:38 – How do we find the mirror points?
- 8:30 – How do we get the normal view directions from Mohr’s circle of inertia?
- 9:05 – Mohr’s circle in the case where x is a horizontal axis.
The PDF of the content in this video can be downloaded by clicking the following buttons.
For more information on the data included in the Video for Mohr’s circle of inertia case 2. Refer to post-8-Easy Approach to Mohr’s circle of inertia-second case.
The Next video is video 8-Video for a solved problem for Mohr’s circle of inertia case 2.