brief introduction for Post 1A-Numerical analysis -part 2

1a-What is synthetic division? Numerical Analysis-part 2

Last Updated on October 6, 2024 by Maged kamel

What is synthetic division? Numerical Analysis-part 2

As an introduction to numerical analysis, we will review synthetic division. Synthetic division is a shorthand, or shortcut, method ofย polynomial division. In the special case of dividing by a linear factor, itย onlyย works in this case.

Synthetic division is generally used not to divide factors but to find zeroes (or roots) of polynomials.

In synthetic division, to get the zero of the function, sometimes, we are guessing the value of the X with so-called rational roots. The rational Root is a handy way of obtaining a list of first guesses when you are trying to find the Zeros of the polynomial.

A Solved problem #1- for synthetic division.

In our example. Y = x ^2 – 5 x + 6. We have a leading coefficient of x^2 = +1. This one can be analyzed at the multiplication (+1*+1)=1, and( -1*-1 )will give us 1, while the 6, the constant, can be analyzed. as either (1*6) or(-1*-6) or (+2*+3) or (-2*-3).
ย So we have 1, and 6 + and – will put it here.

ย And for the leading coefficient, we have 1 and 1 + and -(1*1),(-1*-1).

We put it down here in the denominator and comma; plus or minus, we have 3 either plus or minus divided by the leading coefficient. Now we will Proceed to make the synthetic division. We are writing the coefficients only without the x^2 or x for x^2.ย The coefficient of x^2 is 1.

We put ย (+1*+6),(-1*-6),(+2*3),(-2*-3).The first guess is (x+3)=0 for the first time. X will be = – 3, will go there. We Put – 3 here at the left side portion. The coefficient of x ^2 or the first coefficient. It will go down as 1.

What is synthetic division?A solved example to get a solution for a function.

Then we multiply one by -3; we put it here, add -5 to -3, and get -8. Then we multiply -3 by -8. -8 multiplied by -3 gives us + 24, which we put here, and we add 24+6. We get + 30; as long as we do not get the zero, this point is not a root point, so we proceed with guessing another value. So these are the steps.

1-Our next guess is (x-2)=0; the coefficient of x ^2 will be carried down, multiplied by (+2), then add -+5 to add to +2, and we will get -3.
2-(-3) to be carried down, again multiply by(+2), we will have (-6), add to +6, we get a zero, this means that (x-2) is a zero point. Our solution x- 2 is one of the solutions.

3- we utilize (x-3), the next guess is (x-3), we use +3, 1 will go down, multiply (+13)=3, add to (-3), we get zero value.

4- the two roots are (x-2) and (x -3 ). Now multiply by each other, and you will have (x^2-5x+6) as the same function y=(x^2-5*x+6).

Continue solving the function for roots.

The next slide image shows the graphical solution of the previous function, which tabulates different values of x and estimates the corresponding y value.

A graphical representation for the function.

A solved problem for a synthetic division with a remainder.

The next slide image shows the division of f(x)=x^3-2x^2+x-3 by(x-2) using synthetic division. There will be a remainder of (-1).

Solved problem with a remainder.


A Solved problem for dividing a given function by a value.

Our new function is

1- It is required to divide the function by(x+2).
2- We have the following coefficients: for x^5 is 4, for x^4=0, for x^3=+6, for x^2=-9, for the constant is +6

3- We start with the solution of (x+2)=0; we divide by (-2).
4- number 5 will continue down, multiplied by -2, the product which is -10 will be placed as a second item and added to +6, the value will be -4.

The Second solved example to divide a function by value by synthetic division.

5- (-4) is to be multiplied by -2, and the product, which is=+8, will be placed as a third item.
6- Add +8to(-9), and the value is -1 to be placed down.
We proceed to step 8, as shown in the next slide image.

The Second solved example steps for solution.

Since we have no zero value, a remainder will be expressed as shown in the next slide image.

The Second solved example steps for solution.

A Solved problem for dividing a given function by a value-long division.

The same problem will be solved by using the long division procedure; instead of putting (-2), we will use(x+2).

Solving a problem for root by using long division.

The values 5x^4+6x^3-9x^2-7x+6 will be written on the right side of the (x+2). Divide 5x^4/x=5x^3.
Multiply(5x^3)*(x+2)=5x^4+10x^3. Subtract this value from (5x^4+6x^3). The result will be -4x^3.

Divide -4x^3/x=-4x^2.
Multiply(-4x^2)*(x+2)=-4x^3-8x^2.+10x^3. Subtract this value from (-4x^3-9x^2. The result will be -x^2.

Solved example for long division part 2.

Divide -x^2/x=-x.

Solved example for long division part 3.

Multiply(-x)*(x+2)=-x^2-2x. Subtract this value from (-x^2-7x+6. The result will be -5x+6.

Solved example for long division part 4

Divide -5x /x=-5. Multiply( -5 )*(x+2)=-5x-10.

Solved example for long division part 5.

Subtract (- 5x-10) from (- 5x+6). The result will be 16. There will be a remainder of 16/x+2. The full details are shown in the next slide image.

Solved example for long division part 6.

The next post concerns the Bisecting method, a numerical method for rooting findings.

A very intersection source is Holistic Numerical methods.