Last Updated on October 22, 2026 by Maged kamel
Video for Ixy at CG-right-angle case 2.
How can we derive an expression for the Product of Inertia at the CG of a right-angle triangle- case 2? We use the information we get for the Ixy value about the X and Y axes at the left edge.
Timestamps of the video:
- 0:00- Product of Inertia Ixy at the CG for the right-angle case 2, using the parallel axes theorem.
- 2:02- The Value of Ixy at the CG for a right-angle Triangle, case -2.
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Please refer to the previous video, No. 16-Video, for the product of inertia-right-angle case 2.
The related post is Post 12: Product of Inertia Ixy for the right-angle case 2.
The following video is 18: Ix for a triangle.