Last Updated on September 19, 2026 by Maged kamel
Available Strength for slender W section-CM#15.
We will solve problems 5-10 that have already been addressed based on CM#14 in the previous two posts: Post 16 and Post 16a. Based on the unified Design of the steel structure, our column section for local Buckling is W16x26. Kl in the y-direction = 6.00 ft. The solution is based on CM#15, AISC-360-16. I chose a height of 6 ft to check our estimate with Table 6-2.
Determine the available Strength of a compression member with a slender Web. The section is a W16x26 column with lcy = 6.0 ft.
Check whether the column is slender. From Table 1-1, we have a C note, indicating that column W16x26 is slender. From the same Table, we record Ix, rx, Iy, and ry. The lc/ry Value is (6×12/1.12) = 64.29. Please refer to the following slide image for more details.
In the next two slides. We can see the full details of the W16x26 from Table 1-1.
It is essential to find the Web height, h. We use the ratio h/t, then multiply it by (the Web thickness)s. The Web height equals 14.20 inches.
Is a column slender or not?
We will check against 0.56*sqrt(E/fy), which yields 13.49 > bf/2tf for the Flange in problem 5-10, indicating the Flange is non-slender.
While the Value for W16x26, with (hw/tw) = 56.80, is given in the Table, the limiting Value is 1.49*sqrt(E/fy), which yields 33.72. This Value is less than 56.80, so the section is slender-webbed.
For the relevant data on slender columns, we refer to Chapter E, titled “Design of Members for Compression.” We check section E7 for members with slender elements.
What sections in the code cover slender members?
Chapter E is the Chapter that covers the Design of members for compression; for slender members, we refer to Section E7. Please refer to the next two slide images.
Based on the cross-section, refer to Section E7 in the specification for more information on the relevant equations and different terms related to slender W sections.
Nominal Load for slender column.
The following slide image shows the equation for the Nominal Load of slender compression members, which equals the Product of the effective Area and the critical stress.
There are two conditions based on the Value of h/tw, whether it is smaller or larger than Lambda*sqrt (Fy/Fcr), which indicate whether we need to revise the Web height or keep the same Value.
Check whether the column is inelastic.
We check whether the column is inelastic by comparing the controlling lambda Value of 113.43 with the column’s actual Le/ry, which equals 64.286. Since Le/ry is less than 113.43, the column is inelastic, and we can get the Fcr Value.
We estimate the column’s critical stress based on λ^2. The Fcr Value equals 36.99 ksi, and the Euler stress equals 69.30 ksi. Please refer to the image on the next slide.
How to estimate the effective Web length?
The controlling lambda for the Web ratio is changed to c3*sqrt(E/Fy, instead of 1.49*sqrt(E/Fy based on Table 4.1a, since Fcr will govern the stress.
The following slide image shows the controlling factor C3, which equals 1.49, the same Value as the Web factor in Table B4.1a.
To determine whether to use the Web height unchanged in our effective-area calculation, we need to find the controlling lambda ratio, which equals 1.49*sqrt(29000/36.99) = 41.72. Since this ratio is less than the column h/tw, we need to modify the Web height and use the Expression as in E7-3.
We need to estimate the Fel, or the elastic local Buckling stress, which depends on C1, C2, Fy, λ, and λ̄. The final Value, as shown in the following slide image, equals 34.24 ksi.
The following slide shows the detailed estimate of the effective Web length.
The following slide shows the detailed estimate of the effective Web Area and how to calculate the Nominal Load.
Estimate the Strength Value for the column as LRFD Value = Φc*Pn = 0.90*257.5 = 231.75 kips. For the ASD vaValuePn/Ω = 7.257.5/1.67 = 154.0 kips.
We can compare our estimated factored Loads with the values included for a W16x26 column with ley = 6 ft. These values are very close to our estimates. Thanks a lot.
You can view and download the PDF for this Post from the following Link.
This is the next Post, 17, links to Alignment chart part 2.
For a good Beginner’s Guide to the Steel Construction Manual, 14th ed. Chapter 7 – Concentrically Loaded Compression Members.
For a good A Beginner’s Guide to the Steel Construction Manual, 15th ed. Chapter 7 – Concentrically Loaded Compression Members.
For a good A Beginner’s Guide to the Steel Construction Manual, 16th ed. Chapter 7 – Concentrically Loaded Compression Members.