21-Solved problem 4-16 for k value using the French equation.

Last Updated on March 11, 2026 by Maged kamel

Solved problem 4-16 for k value by using the French equation.

Our solved problem, 4-16, from Prof. Alan Williams’s book, Structural Engineering Reference Manual.

Details of solved problem 4-16.

The sway-inhibited frame means an Unbraced, Unstiffened frame. The sway frame is shown, consisting of members with identical I/L values. It is required to determine the effective length factor for columns 12 and 34.
He has not included any values for the length of girders or the height of columns. We can consider that h and L are the same. It is required to obtain the K value for columns 12 and 34.

Solved problem 4-16 is required to determine the effective length factors for two columns of a frame.

We have solved problem 4-16 in the previous post. I wanted to attach a copy of the solved problem and the author’s solution. The solution is summarized, but at least we have arrived at our final result with more detailed steps.

Verify the K value using the French equation against the Nomograph.

The French equation was made for side sway uninhibited-unbraced frame, for the k value, which is k=sqrt(1.6*GA*Gb+4(Ga+Gb)+7.5)/ sqrt of(GA+Gb+7.5).

 Let’s try our solved problem 4-16 from Prof. Alan Williams’s book. As a remark for our Sway frame, our side-sway is Uninhibited for Ga=0, Gb=0, and K =1 from the Nomograph chart.

Let us use the French equation. First, check the value of k provided by the French equation against the K value obtained from the Nomograph. Put Ga=Gb=0 and substitute, then K=sqrt(0+)0+7.7, the denominator sqrt(0+0+7.5), then k=sqrt(7.5/7.5)=1, k=1.

This value matches the k obtained from the Nomograph. Let us try for Ga=Gb=100. From the chart, it is approximately k=9. The Nomograph, rather, has a narrow view, based on the French equation k = sqrt (1.6100100 + 7.5) / sqrt(100 + 100 + 7.5).

Verify Nomograph with the French equation

K value for the first column 12 by using the French equation.

Let us refer back to the solved problem 4-16, which consists of two parts. The first part is the hinged support at joint 1, and the second part is for the corner joint 2. G1=10 at the hinged support, while G=1 for joint 2, k from the graph was 1.9.

Using the French equation to get the value for K, then k=sqrt(1.6(10)(1)+4*(10+1)+7.5)/ sqrt (10+1+7.5), sqrt (10+1+7.5), using an Excel sheet, we get k=1.90414, which is close to k=1.9 from the nomograph to some extent.

Using the French equation -Solved problem 4-16 for column 12.

K value for the first column 34 by using the French equation.

The second part of the solved problem 4-16 for fixed support, and the joint was ended by a pinned support at the far point, while at the near joint was a corner, where m, for the far end, while m=1/2, k was =1.27 from Nomograph.

Using the French equation, we get the k value as k = sqrt (1.60.671 + 4*(2/3 + 1) + 7.5)/ sqrt(0.67 + 1 + 7.5), then k = 1.289, which is close to the exact value used to find a closer figure for the K value estimate by the Nomograph.

Using the French equation -Solved problem 4-16 for column 34.

The PDF for this post is available for viewing and download in the document below.

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