Last Updated on July 28, 2026 by Maged kamel
Video for the parallel axes theorem for the moment of inertia.
An introduction to the parallel axes theorem. The video explains how we can find the expression for the moment of inertia about an external Y-axis by adding the moment of inertia about the CG to the product of the area and the square distance from the CG to that external axis.
Similarly, the product of the area about two external axes equals the product of the area at the CG plus the area by the x distance times the y distance from the CG to these axes. The polar moment of inertia at the intersection of any two axes is equal to the polar moment of area at the same point for any other two orthogonal axes passing through the same point.
The Timestamps for the video are shown.
[presto_timestamp time=”0:00″]0:00[/presto_timestamp] –The proof of the parallel axes theorem for Iy.
[presto_timestamp time=”3:23″]3:23[/presto_timestamp] –Part a, the proof of the parallel axes theorem for Ixy.
[presto_timestamp time=”5:11″]5:11[/presto_timestamp] –Part b, the proof of the parallel axes theorem for Ixy.
[presto_timestamp time=”6:30″]6:30[/presto_timestamp] -The polar moment of inertia, parallel axes theorem.Ixy.
[presto_timestamp time=”8:22″]8:22[/presto_timestamp] -The radius of gyration Kx and Ky.
The first video link: 1-video for introducing the moment of inertia.
The related post is Post 2-Parallel axes theorem for Iy, polar moment of inertia.
A newly added video, 3-Video for Ix for a rectangular section.